Java program that reads an integer and prints how many digits the number has
Posted by Samath
Last Updated: February 11, 2021
  694

Write a Java program that reads an integer and prints how many digits the number has, by checking whether the number is ≥ 10, ≥ 100, and so on. (Assume that all integers are less than ten billion.) If the number is negative, first multiply it by –1.

Code:

import java.util.Scanner;

public class Main
{
	public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        
        System.out.print("Please Enter Number: ");
        long inp = input.nextInt();
        input.close();
        
        int result = 1;
        if (inp < 0) inp *= -1;
        if (inp >= 10 && inp < 100)
        {
            result = 2;
        }
        else if (inp >= 100 && inp < 1000) 
        {
            result = 3;
        }
        else if (inp >= 1000 && inp < 10000)
        {
            result = 4;
        }
        else if (inp >= 10000 && inp< 100000)
        {
            result = 5;            
        }
        else if (inp >= 100000 && inp < 1000000)
        {
            result = 6;            
        }
        else if (inp >= 1000000 && inp < 10000000)
        {
            result = 7;
        }
        else if (inp >= 10000000 && inp < 100000000)
        {
            result = 8;            
        }
        else if (inp >= 100000000 && inp < 1000000000)
        {
            result = 9;
        }
        else if (inp >= 1000000000 && inp < 1000000000)
        {
            result = 10;
        }
        else
        {
            System.out.println("Number is greater than 10 billion.");
        }
        System.out.printf("Result: %d", result);
    }
}