C++ Summing the digits in an integer
Posted by Samath
Last Updated: January 06, 2021
  6688

Write a program that reads an integer between 0 and 1000 and adds all the digits in the integer. For example, if an integer in 932, the sum of all its digits is 14.

(Hint: Use the % operator to extract digits, and use the / operator to remove the extracted digit. For instance, 932 % 10 = 2 and 932/10 = 93.)

Solution:

#include <iostream>
using namespace std;
int main(int argc, char *argv[])
{
	int number;
	int sep1;
	int sep2;
	int sep3;
	int sep4;
	int sum;
	
	cout<<"Enter a number between 0 and 1000: ";
	cin>>number;
	
	if(number > 0 && number < 1000)
	{
	    	sep1 = number % 10; 
	sep2 = number/10;
	
	if(number >= 100)
	{
	sep3 = sep2 % 10; 
	sep4 = sep2/10;
	sum = sep1 + sep3 + sep4;
	}
	else
	{
	sum = sep1 + sep2;	
	}	
	cout<<"Total: "<<sum<<endl;
	}
	else
	{
		cout<<"Invalid Number"<<endl;
	}
	system("pause");
	
	return 0;
}