Convert ASCII Character to Hexadecimal and Binary using C++
 Posted by Samath Last Updated: January 05, 2017   643

This program ask the user for a ASCII Character and convert it to Hexadecimal and Binary.

Hexadecimal is a positional numeral system with a radix, or base, of 16. It uses sixteen distinct symbols, most often the symbols 0–9 to represent values zero to nine, and A, B, C, D, E, F (or alternatively a, b, c, d, e, f) to represent values ten to fifteen.

```#include <iostream>
using namespace std;

int x;
char xa;
int y;
int n = 0;
int i = 0;
int a = 0;
int binary[8] = { 128, 64, 32, 16, 8, 4, 2, 1 };
int binaryout[8];
int nibbleone[4];
int nibbletwo[4];
char hexvalue[16] = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F' };
int b;
int c;
int d;
int e;

int main()
{
cout << "Input any character: ";
cin >> xa;
x = xa;
cout << "ASCII value: " << x << endl;

for (y = 0; y <= 7; y++)
{
if (x == 0)
{
break;
}
if (x - binary[y] >= 0)
{
x -= binary[y];
binaryout[n] = 1;
n += 1;
}
else if (x - binary[y] < 0)
{
n += 1;
}
}

cout << "Binary Value: ";

for (i = 0; i <= 7; i++)
{
cout << binaryout[i];

if (i < 4)
{
nibbleone[a] = binaryout[i];
a += 1;
}
else if (i == 4)
{
a = 0;
nibbletwo[a] = binaryout[i];
a += 1;
}
else if (i > 4)
{
nibbletwo[a] = binaryout[i];
a += 1;
}
}

e = 4;

for (d = 0; d <= 3; d++)
{
if (nibbleone[d] == 1)
{
b += binary[e];
e += 1;
}
else if (nibbleone[d] == 0)
{
e += 1;
}
}

cout << endl << "Hex value: " << hexvalue[b];

e = 4;

for (d = 0; d <= 3; d++)
{
if (nibbletwo[d] == 1)
{
c += binary[e];
e += 1;
}
else if (nibbletwo[d] == 0)
{
e += 1;
}
}

cout << hexvalue[c] << endl;

int end;
cin >> end;
}```