Write a C program that takes a 2 digit hexadecimal number from the user through console and display it in binary format.
Code:
- #include <stdio.h>
- int main (int argc, char * const argv[]) {
- // In this part we create an array of 2 characters
- char number[2];
- int i;
- printf("Please enter a 2 digit hexadecimal number\n");
- // Here it scans the number given and stores it in the array
- scanf("%s", number);
- // It starts to create a loop from 0 to 2 checking each number
- for(i=0; i<2; i++){
- //If the number is equal to one number in hexadecimal it print in
- //the binary format
- if(number[i] == '0'){
- printf("0000");
- }
- else if(number[i] =='1'){
- printf("0001");
- }
- else if(number[i] == '2'){
- printf("0010");
- }
- else if(number[i] == '3'){
- printf("0011");
- }
- else if(number[i] == '4'){
- printf("0100");
- }
- else if(number[i] == '5'){
- printf("0101");
- }
- else if(number[i] == '6'){
- printf("0110");
- }
- else if(number[i] == '7'){
- printf("0111");
- }
- else if(number[i] == '8'){
- printf("1000");
- }
- else if(number[i] == '9'){
- printf("1001");
- }
- else if(number[i] == 'A' || number[i] == 'a'){
- printf("1010");
- }
- else if(number[i] == 'B' || number[i] == 'b'){
- printf("1011");
- }
- else if(number[i] == 'C' || number[i] == 'c'){
- printf("1100");
- }
- else if(number[i] == 'D' || number[i] == 'd'){
- printf("1101");
- }
- else if(number[i] == 'E' || number[i] == 'e'){
- printf("1110");
- }
- else if(number[i] == 'F' || number[i] == 'f'){
- printf("1111");
- }
-
- else {
- printf( "You did not follow the rules\n" );
- }
- }
- printf( "\n" );
- return 0;
- }