Java program that asks the user for a year and computes whether that year is a leap year
Posted by Samath
Last Updated: May 08, 2021
  449

A year with 366 days is called a leap year. Leap years are necessary to keep the calendar synchronized with the sun because the earth revolves around the sun once every 365.25 days. Actually, that figure is not entirely precise, and for all dates after 1582 the Gregorian correction applies. Usually, years that are divisible by 4 are leap years, for example, 1996. However, years that are divisible by 100 (for example, 1900) are not leap years, but years that are divisible by 400 are leap years (for example, 2000).

Write a program that asks the user for a year and computes whether that year is a leap year. Use a single if statement and Boolean operators.

Code:

import java.util.Scanner;

public class Main
{
  public static void main(String[] args) {
      
	Scanner input = new Scanner(System.in);
	int year;
	boolean leapYear;
	
	System.out.print("Enter year: ");
	year = input.nextInt();
	input.close();
	
	leapYear = false;
	if ((year % 100 != 0 && year % 4 == 0) || year % 400 == 0) {
	    leapYear = true;
	}
	
	if(leapYear == true)
	{
	    System.out.printf("%d is a leap year.", year);
	}
	else
	{
	    System.out.printf("%d is not a leap year.", year);
	}
	
    }
}