Question: Converting data Posted by kevaughn Last Updated: July 01, 2014 1177 Anyone knows a method to convert hexadecimal data to binary and from that binary data to decimal. So the output will be in decimal format. Data is in a txt file where i used the bufferedreader method to read the hexadata. Font NameReal font size Samath binary data to decimal int binary_to_decinal (char bin[]){ int c,x=0,i,factor=1; int decimal=0; int len; len = strlen (bin)-1; for (i=0;i<=len;len--){ if (bin[len]==49){ c=bin[len]-48;} else if (bin[len]==48){ c=bin[len]-48;} decimal = decimal + c*factor; factor = factor*2; } return decimal; } Delete Comment Samath binary data to decimal void hexadecimal_to_binary() { char binaryNum[100],hexaDec[100]; int i=0; printf("Enter hexadecimal number: "); scanf("%s",hexaDec); printf("\The binary value of the hexadecimal number is: "); while(hexaDec[i]) { switch(hexaDec[i]) { case '0': printf("0000"); break; case '1': printf("0001"); break; case '2': printf("0010"); break; case '3': printf("0011"); break; case '4': printf("0100"); break; case '5': printf("0101"); break; case '6': printf("0110"); break; case '7': printf("0111"); break; case '8': printf("1000"); break; case '9': printf("1001"); break; case 'A': printf("1010"); break; case 'B': printf("1011"); break; case 'C': printf("1100"); break; case 'D': printf("1101"); break; case 'E': printf("1110"); break; case 'F': printf("1111"); break; default: printf("\nInvalid hexadecimal digit %c ,hexaDec[i]); return 0; } i++; } } Delete Comment