Question: Converting data
 Posted by kevaughn Last Updated: July 01, 2014   1177

Anyone knows a method to convert hexadecimal data to binary and from that binary data to decimal. So the output will be in decimal format. Data is in a txt file where i used the bufferedreader method to read the hexadata.

 binary data to decimal ```int binary_to_decinal (char bin[]){        int c,x=0,i,factor=1;      int decimal=0;      int len;        len = strlen (bin)-1;        for (i=0;i<=len;len--){             if (bin[len]==49){                c=bin[len]-48;}             else if (bin[len]==48){                c=bin[len]-48;}          decimal = decimal + c*factor;          factor = factor*2;      }          return decimal;  }```
 ` binary data to decimal` ```void hexadecimal_to_binary() {     char binaryNum[100],hexaDec[100];      int i=0;     printf("Enter hexadecimal number: ");     scanf("%s",hexaDec);     printf("\The binary value of the hexadecimal number is: ");       while(hexaDec[i])      {         switch(hexaDec[i])         {              case '0': printf("0000"); break;              case '1': printf("0001"); break;              case '2': printf("0010"); break;              case '3': printf("0011"); break;              case '4': printf("0100"); break;              case '5': printf("0101"); break;              case '6': printf("0110"); break;              case '7': printf("0111"); break;              case '8': printf("1000"); break;              case '9': printf("1001"); break;              case 'A': printf("1010"); break;              case 'B': printf("1011"); break;              case 'C': printf("1100"); break;              case 'D': printf("1101"); break;              case 'E': printf("1110"); break;              case 'F': printf("1111"); break;              default:  printf("\nInvalid hexadecimal digit %c ,hexaDec[i]);              return 0;          }          i++;      } }```