With the aid of a while loop create a C++ program that finds the sum all the even numbers between 1 and 30. Do not include the numbers 6, 8, 24 and 28 in the final accumulation of these even numbers.
Here is the Solution to the problem above:
#include <iostream>
using namespace std;
int main(int argc, char *argv[])
{
int count = 1, sum = 0;
while (count < 30)
{
if(count % 2 == 0)
{
if(count!=6 && count!=8 && count!=24 && count!=28)
{
sum += count;
}
}
count ++;
}
cout<<"Result: "<<sum;
cout<<endl;
return 0;
}