Write a c program to check whether the given matrix is a magic square matrix or not? A magic square is a simple mathematical game developed during the 1500.Square is divided into equal number of rows and columns.Start filling each square with the number from 1 to num ( where num = No of Rows X No of Columns ).You can only use a number once.Fill each square so that the sum of each row is the same as the sum of each column.

Code:

#include<stdio.h>
#include<conio.h>
 
int main() {
   int size = 3;
   int matrix[3][3]; 
   int row, column = 0;
   int sum, sum1, sum2;
   int flag = 0;
 
   printf("\nPlease Enter matrix : ");
   for (row = 0; row < size; row++) {
      for (column = 0; column < size; column++)
         scanf("%d", &matrix[row][column]);
   }
 
   printf("Matrix: \n");
   for (row = 0; row < size; row++) {
      printf("\n");
      for (column = 0; column < size; column++) {
         printf("\t%d", matrix[row][column]);
      }
   }
 
   
   sum = 0;
   for (row = 0; row < size; row++) {
      for (column = 0; column < size; column++) {
         if (row == column)
            sum = sum + matrix[row][column];
      }
   }
 
   
   for (row = 0; row < size; row++) {
      sum1 = 0;
      for (column = 0; column < size; column++) {
         sum1 = sum1 + matrix[row][column];
      }
      if (sum == sum1)
         flag = 1;
      else {
         flag = 0;
         break;
      }
   }
 
   
   for (row = 0; row < size; row++) {
      sum2 = 0;
      for (column = 0; column < size; column++) {
         sum2 = sum2 + matrix[column][row];
      }
      if (sum == sum2)
         flag = 1;
      else {
         flag = 0;
         break;
      }
   }
 
   if (flag == 1)
      printf("\nMagic square");
   else
      printf("\nNo Magic square");
 
   return 0;
}